Activity Booklet Shobhit Nirwan Science 10th 2024
Activity Booklet Shobhit Nirwan Science 10th 2024
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Formation of Precipitate
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Decomposition reaction of ferrous sulphate.
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Decomposition of silver chloride is caused by light
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Double displacement reaction between barium chloride and
sodium sulphate.
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Ch-2: Acids, Bases and Salts
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Take a boiling tube and put about 0.5 g of sodium carbonate in it.
Add aboutChalo
2 mLAbof Ise AASAN
dilute BHASHA
hydrochloric acid inMEI Samajhte
the boiling hai : a
tube (through
Take about 2 cm long magnesium ribbon .
thistle funnel)
Clean
We will observe that brisk it with sand
effervescence of a paper.
gas is produced.
HoldPass
the the
magnesium
gas throughribbon with
lime water. Thea lime
pairwater
of tongs , and(showing
turns milky start heating
that it is its
carbon dioxide gas). other end.
Keep on passingThe Magnesiumgas
carbon dioxide through
Ribbon milky lime
starts water for some more
burning.
time. The lime water becomes clear again.
BUT IT'S NOT BURNING ALONE.
This shows that the white precipitate of calcium carbonate dissolves on passing
It starts burning with a WHITE DAZZLING FLAME .
excess of carbon dioxide gas. We can repeat this experiment by using sodium
And now to collect
hydrogencarbonate the
in place ofMagnesium Oxide
sodium carbonate. Powder
Again we willhold it over a
get carbon
dioxide gas which will turn lime waterWatchmilky.Glass
On passing excess of carbon dioxide,
the milky lime water will become clear again.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
BUT IT'S NOT BURNING ALONE.
It starts burning with a WHITE DAZZLING FLAME .
And now to collect the Magnesium Oxide Powder hold it over a
Watch Glass
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Adding Acid/Base in Water
Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
BUT IT'S NOT BURNING ALONE.
Chalo
It starts Ab Ise AASAN
burning with aBHASHA
WHITEMEI Samajhte hai
DAZZLING :
FLAME .
The process of dissolving an acid or a base in water is a highly exothermic one.
And now to collect the Magnesium Oxide Powder hold it over a
Ans-
Watch Glass
i. Yes beaker becomes hot on adding H2SO4 (Acid)
ii. Exothermic reaction took place.
iii. Na2SO4, NaCI, NaNO3 and Na2CO3 belong to the family of sodium salts.
K2SO4, Na2SO4, CaSO4, MgSO4, CuSO4 belong to the family of sulphate
salts.
NaCI and KCI belong to the family of chloride salts.
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pH, Acids and Bases Used
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Ch-3: Metals and Non-Metals
Chalo Ab
Metals, in Ise AASAN
their BHASHA
pure state, MEI
have Samajhte
a shining hai :
surface.
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
BUT IT'S NOT BURNING ALONE.
Metals, in their pure state, have a shining surface.
It starts burning with a WHITE DAZZLING FLAME .
So, before rubbing and cleaning with sample paper, metals had less shiny surface.
And
After now to
rubbing andcollect
cleaningthe
withMagnesium Oxide
sand paper, they'll Powder
become morehold
shiny.it over a
Watch Glass
Chalo
Some Abmetals
Ise AASAN BHASHA
can be beatenMEIintoSamajhte
thin sheets hai :
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium
Chalo Ab Ise AASANRibbon
BHASHA MEIstarts burning.
Samajhte hai :
We observed that some BUT IT'Scan
metals NOTbe BURNING ALONE.
beaten into thin sheets. This property is
It starts burning with a WHITE DAZZLING FLAME .
called malleability.
Gold
And now toare
and silver the most
collect themalleable metals Oxide Powder hold it over a
Magnesium
Watch Glass
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Metals are good conductors of heat and have high melting points
Chalo AbMetals
Ise AASANalso BHASHA MEI Samajhte hai :
conduct electricity
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
i. On placing the metalBUT IT'S
in the NOTbetween
circuit BURNING ALONE.
terminals A and B, we find that the
bulb glows. It starts burning with a WHITE DAZZLING FLAME .
ii. And now that
This shows to collect thegood
metals are Magnesium Oxide
conductor of Powder
electricity too. hold it over a
Watch Glass
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
i. Take a magnesium ribbon and some sulphur powder, Burn the magnesium ribbon:
Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
2Mg(s) + 02(g) -> 2MgO(s)
Take about 2 cm long magnesium ribbon .
ii. Collect the ashes formed and dissolve them in water.:
Clean +itH20(I)
MgO(S) with sand paper.
-> Mg(OH)2(aq)
Hold thethe
iii. Testing magnesium ribbon
resultant solution withwith
botharedpair
andof tongs
blue litmus, and start
paper, heating
we find its
it is Basic
Mg(OH)2. other end.
iV. Now burn sulphur The Magnesium
powder. Ribbon
Place a test starts
tube over burning.
the burning sulphur to collect the
fumes produced: BUT IT'S NOT BURNING ALONE.
S(s) + 02(g) -› SO2(g)
It starts burning with a WHITE DAZZLING FLAME .
v. Add some water to the above test tube and shake:
And now to collect the Magnesium Oxide Powder hold it over a
S02(g) + H20(1) - H2S03 (aq)
vi. Testing this solution with blue andWatch Glass
red litmus paper, it is acidic Sulphuric Acid,
H2SO3.
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Reaction of metals with Steam
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What happens when Metals react with Acids?
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CORROSION
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Ch-4: CARBON
(i) Yes, there is a similarity in the difference between their molecular formulae and
molecular masses. Their molecular formulae differ by CH2 (1 carbon atom and 2
hydrogen atoms), and their molecular masses differ by 14 u.
(ii) These alcohols can be arranged in the order of the increasing carbon atoms as
follows : CH3OH, C2H5OH, C3H7OH, C4H9OH
Yes, we can call it a homologous series.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Limiting the supply of air results in incomplete combustion of even saturated
hydrocarbons giving a sooty flame
When do you get a flame? - In presence of a sufficient supply of air with oxygen, it
gives a blue flame.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
This is esterification reaction,
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Ch-5: Life Processes
Activity to demonstrate that Chlorophyll is necessary for
Photosynthesis
Question 1. What happens to the colour of the leaf? What is the colour of the
solution?
Answer. The green leaf becomes colourless. On immersing green leaf in a alcohol,
chlorophyll responsible for its green colour gets dissolves in alcohol. The colour of
the alcohol solution turns green
Question 2. What can you conclude about the presence of starch in various
areas of the leaf?
Answer. The green areas of leaf, which turns dark blue on dipping in iodine
solution, indicate the presence of starch where as colorless part of leaf show no
formation of starch. From this activity we can conclude that chlorophyll is essential
for photosynthesis
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Activity to show that amount of Carbon Dioxide (CO2), essentially
affects the process and outcome of Photosynthesis
ChaloChalo
Ab Ise AASAN
Ab Ise AASANBHASHA
BHASHA MEIMEI Samajhte
Samajhte hai : hai :
Take potted
Take two healthy aboutplants
2 cmwhichlong are
magnesium ribbon
nearly the same size..
Keep them in a dark roomClean for it with
three sand paper.
days.
Hold the magnesium ribbon with a pairplates.
Now place each plant on separate glass Place,aand
of tongs watch-glass
start heating its
containing potassium hydroxide by the side of one of the plants. The
other end.
potassium hydroxide is used to absorb carbon dioxide.
The Magnesium Ribbon starts burning.
Cover both plants with separate bell-jars as shown in Fig. .
BUT IT'S NOT BURNING ALONE.
Use Vaseline to seal the bottom of the jars to the glass plates so that the set-
It starts burning with a WHITE DAZZLING FLAME .
up is air-tight.
And now
Keep the to collect
plants the Magnesium
in sunlight Oxide Powder hold it over a
for about two hours.
Pluck a leaf from each plant and WatchcheckGlass
for the presence of starch as in the
above activity.
Question 1. Do both the leaves show the presence of the same amount of
starch?
Answer. No, both the leaves do not show the presence of the same amount of
starch, because in photosynthesis starch is produced using sun light, chlorophyll
and CO2. In first set up availability of CO2 will be less for making starch by the
plant leaves, as potassium hydroxide (KOH ) absorb the CO2. In second plant
setup, the leaves will have more amount of starch.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
Chalo Ab Ise AASAN other end.MEI Samajhte hai :
BHASHA
Thesolution
Take 1 mL starch Magnesium Ribbon
(1%) in two starts
test tubes burning.
(A and B).
Add 1 mL saliva toBUT IT'S ANOT
test tube BURNING
and leave ALONE.
both test tubes undisturbed for 20-30
It starts burning with a WHITE DAZZLING FLAME .
minutes.
And
Nownow
add a tofew
collect the
drops of Magnesium
dilute Oxide
iodine solution Powder
to the hold it over a
test tubes.
Question 1. In which test tube doWatchyou observe
Glass a colour change?
Answer. We will observe a colour change in test tube B, showing presence of
starch. Where as test tube A will show no colour change as due to addition of
saliva, starch is converted into sugar.
Question 2. Note how long it takes for this lime water to turn milky?
Answer. When we use syringe or pichkari, to pass air through the lime solution, it
takes much time and effort to turn the lime water milky.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Take about 2 cm long magnesium ribbon .
Chalo AbClean it with
Ise AASAN sand MEI
BHASHA paper.
Samajhte hai :
Hold the
Takemagnesium ribbon
some fruit juice with
or sugar a pair
solution andof tongs
add some ,yeast
and tostart
this. heating
Take this its
other
mixture in a test tube fitted with end. cork.
a one-holed
Fit the cork The
with aMagnesium
bent glass tube. Dip thestarts
Ribbon free end of the glass tube into a
burning.
test tube containing
BUTfreshly prepared
IT'S NOT lime water.
BURNING ALONE.
It starts burning with a WHITE DAZZLING FLAME .
Question 1. What change is observed in the lime water and how long does it
And now to collect the Magnesium Oxide Powder hold it over a
take for this change to occur?
Answer. The lime water becomesWatch milky asGlass
carbon dioxide is produced by mixing
yeast in sugar along with alcohol. Time taken for this change to occur, should be
observed by students themselves.
Question 2. What does this tell us about the products of fermentation?
Answer.The products of fermentation are alcohol and carbon dioxide.
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Ch-6: Control & Coordination
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Ch-7: Reproduction
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Activity Observation: The potato pieces having buds gradually grows and
develops. But there is no growth and development in potato pieces without buds.
Which are the potato pieces that give rise to fresh green shoots and roots?
The pieces with buds give rise to fresh green shoots and roots.
Activity Observation: Portion of Money plant with at least one leaf grows and
gives rise to fresh leaves. But money plant without leaf dies.
Activity Observation: Two seed cotyledons are separated by radicle and plumule
formation.
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Ch-9- Light: Reflection & Refraction
Chalo AbAb
Chalo Ise
IseAASAN BHASHA
AASAN BHASHA MEIMEI Samajhte
Samajhte hai : hai :
Take of
The curved surface about 2 cm
a shining longcould
spoon magnesium ribbon
be considered .
as a curved mirror.
One Convex surface and Clean
other it with sand
concave paper.
surface. Sp for answering the
Holdquestions keep in mindribbon
the magnesium the properties
with aofpair
bothof
thetongs
spherical mirrors.
, and start heating its
Question 1: Do you get the image?other Is it smaller
end. or larger?
Yes. The image on the outer curved surface is smaller.
The Magnesium Ribbon starts burning.
Question 2: Move the spoon slowly away from your face. Observe the image.
How does it change?
BUT IT'S NOT BURNING ALONE.
It starts
The size of the burningdecreases.
image gradually with a WHITE DAZZLING FLAME .
And now
Question to collect
3: n Reverse the Magnesium
the spoon and repeat the Oxide Powder
Activity. How hold it over a
does the
image look like now? Watch Glass
The image at its concave side is real, inverted and diminished.
Question 4: Compare the characteristics of the image on the two surfaces.
• The image at its concave side is real, inverted and diminished. If the spoon is
moved away, the image becomes smaller.
• Image at the convex side is virtual, erect & diminished. If the spoon is moved
away, the image becomes smaller.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
This activity is basically to find out the positions of the image formed by the
Take about 2 cm long magnesium ribbon .
convex mirrors, their nature, size etc.
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
BUT IT'S NOT BURNING ALONE.
It starts burning with a WHITE DAZZLING FLAME .
Question 1: Observe the image of the pencil in the mirror. Is the image erect
And now to collect the Magnesium Oxide Powder hold it over a
or inverted? Is it diminished or enlarged?
Watch Glass
Its image in the mirror is erect and diminished.
Question 2: Move the pencil away from the mirror slowly. Does the image
become smaller or larger?
The image becomes smaller.
Question 3: Repeat this Activity carefully. State whether the image will move
closer to or farther away from the focus as the object is moved away from
the mirror?
The image moves closer to the focus.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Chalo
Take Ab Ise 2AASAN
about cm longBHASHA MEI Samajhte
magnesium hai : .
ribbon
These activities are toClean
understand the sand
it with phenomenon
paper.of refraction of light.
Light does not travel in the same direction in all media. It appears that when
Hold the magnesium ribbon with a pair of tongs , and start heating its
travelling obliquely from one medium to another, the direction of propagation
other end.
of light in the second medium changes.
The Magnesium Ribbon starts burning.
Question 1: With your BUT
eye IT'S NOTabove
to a side BURNING
water,ALONE.
try to pick up the coin in one
go. Did youIt succeed
starts burning
in picking with a WHITE
up the coin? DAZZLING FLAME .
NoAnd now to collect the Magnesium Oxide Powder hold it over a
Question 2: Repeat the Activity.Watch Why didGlass
you not succeed in doing it in one
go?
Reflected light coming from the submerged coin in water (denser medium), on
entering air (rarer medium), bend away from the normal due to refraction of light
and image size becomes larger than its actual size. Thus, coin appears to be
closer than its actual distance.
Question 3: Keep looking for the coin from your position. Does the coin
becomes visible again from your position? How could this happen?
Yes. The coin becomes visible again. This is because the coin appears slightly
raised above its actual point due to refraction of light.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Draw a thick straight line in ink, over a sheet of white paper on a table.
Place a glass slab over the line in such a way that one of its edges makes an
angle with the line.
Question: Look at the portion of the line under the slab from the sides.
What do Chalo Ab Ise AASAN
you observe? Does theBHASHA
line underMEI Samajhte
the glass hai : to be
slab appear
bent at theTake
edges?about 2 cm
-- Yes, long
the line magnesium
under ribbon
the slab appears . bent and it
to be
is due to refraction. Clean it with sand paper.
Next, place the glass slab such that it is normal to the line.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
BUT IT'S NOT BURNING ALONE.
It starts burning with a WHITE DAZZLING FLAME .
And now to collect the Magnesium Oxide Powder hold it over a
Watch
Question: What do you observe Glass
now? Does the part of the line under the
glass slab appear bent? -- No, the part of the line under the glass slab does
not appear bent because the ray of light is perpendicular to the slab and does
not make any angle, so it appears straight.
OBSERVATION: This activity demonstrates the phenomenon of refraction and
for normal incidence, there no refraction occurs.
Question: Look at the line from the top of the glass slab. Does the part of
the line beneath the slab, appear to be raised? why does this happen? --
Yes, the part of the line beneath the slab appears to be raised because of
refraction.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
This activity is basically to find out the positions of the image formed by the
convex lens, their nature, size etc.
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Ch-12- Electricity
We observed that approximately the same value for V/I is obtained in each
case. Thus the V–I graph is a straight line that passes through the origin of the
graph, as shown in Fig. 12.3. Thus, V/I is a constant ratio.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
Take about 2 cm long magnesium ribbon .
Clean it with sand paper.
Hold the magnesium ribbon with a pair of tongs , and start heating its
other end.
The Magnesium Ribbon starts burning.
Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
BUT IT'S
This activity is basically NOT
to study BURNING
about electricalALONE.
resistance of a conductor.
It starts burning with a WHITE DAZZLING FLAME .
In this Activity we observe that the current is different for different
And
Whynow to differ?
do they collect the Magnesium
Certain Oxide
components offer Powder
an easy hold
path for theitflow
over
of a
Watch
electrical current while the others resistGlass
the flow.
We know that the motion of electrons in an electric circuit constitutes an
electric current. The electrons, however are not completely free to move within
a conductor. They are restrained by the attraction of the atoms among which
they move.
Thus, motion of electrons through a conductor is retarded by its resistance.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
This activity is basically to understand that the current in the ammeter is the
same, independent of its position in the electric circuit.
It means that in a series combination of resistors the current is the same in
every part of the circuit or the same current through each resistor.
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Ch-13- Magnetic Effects
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
We shall first consider the pattern of the magnetic field around a straight conductor
carrying current.
What happens to the deflection of the compass needle placed at a given point if the
current in the copper wire is changed? To see this, vary the current in the wire. We find
that the deflection in the needle also changes. In fact, if the current is increased, the
deflection also increases. It indicates that the magnitude of the magnetic field produced
at a given point increases as the current through the wire increases.
What happens to the deflection of the needle if the compass is moved away from
the copper wire but the current through the wire remains the same? To see this, now
place the compass at a farther point from the conducting wire (say at point Q).
What change do you observe? We see that the deflection in the needle decreases. Thus
the magnetic field produced by a given current in the conductor decreases as the
distance from it increases.
From Fig. 13.6, it can be noticed that the concentric circles representing the magnetic field
around a current-carrying straight wire become larger and larger as we move away from
it.
Does the direction of magnetic field lines get reversed if the direction of current
through the straight copper wire is reversed? -- The direction of magnetic field lines is
reversed if the direction of current through the copper wire is reversed.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
The displacement of the rod (AB) suggests that:
A force is exerted on the current-carrying aluminium rod when it is placed in a
magnetic field.
The direction of force is also reversed when the direction of current through the
conductor is reversed.
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Chalo Ab Ise AASAN BHASHA MEI Samajhte hai :
As soon as the current in coil-1 reaches either a steady value or zero, the
galvanometer in coil-2 shows no deflection.
We conclude that a potential difference is induced in coil-2 whenever the electric
current through the coil-1 is changing (starting or stopping). Coil-1 is called the
primary coil and coil-2 is called the secondary coil. As the current in the first coil
changes, the magnetic field associated with it also changes. Thus the magnetic field
lines around the secondary coil also change. Hence the change in magnetic field
lines associated with the secondary coil is the cause of induced electric current in it.
This process, by which a changing magnetic field in a conductor induces a current in
another conductor, is called electromagnetic induction
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