EXAMINATION

GRADE 11

TECHNICAL SCIENCES

(PAPER 1)

NOVEMBER 2023

MARKS: 150

MEMORANDUM
Technical Sciences Examination FS/November 2023 MEMO
Grade 11

QUESTION 1: MULTIPLE-CHOICE QUESTIONS

1.1 D 

1.2 D 

1.3 C 

1.4 C 

1.5 B 

1.6 A 

1.7 C 

1.8 B 

1.9 D 

1.10 A 

[20]
Technical Sciences Examination FS/November 2023 MEMO
Grade 11

QUESTION 2

2.1 Forces have both magnitude and direction  (2)

2.2
X- Components Y-Components
OPTION 1 OPTION 2 OPTION 1 OPTION 2
Ax = Acos Ax = Asin Ay = Asin Ay = Acos
= 20cos30 = 20sin60 = 20sin30 = 20cos60
= 17,32 N (left) = 17,32 N (left) = 10 N (up) = 10 N (up)

Bx = Bcos Bx = Bcos By = Bcos  Bx = Bcos
= 25cos40 = 25sin50 = 25sin40 = 25cos50
= 19,15 N (right) = 19,15 N = 16,07 N, (up) = 16,07 N (up)
(right)
Cx = 0N Cy = 35 N (down) Cx = 35 N (down)
Cx = 0 N

Right = + Down = +
Fx = A x + B x + C x F y = A y + B y + Cy
= 19,15 – 17,32 + 0 = 35 – (10 + 16,07)
= 1,83 N  (right) = 8,93 N  (down)

¿ ( 1 , 83 ) + ( 8 , 93 ) F R =9 , 12 N 
2 2 2 2 2
F R =F x + F y

(5)
2.3 POSITIVE MARKING FROM QUESTION 2.2

OPTION 1 OPTION 2
¿ tan
−1 F y
Fx (
¿ tan−1 )
8 , 93
1 ,83
 ¿ tan
−1 F y
Fx (
¿ tan−1
1 ,83
8 , 93)
¿78,42 ¿11,58
Bearing = 90 + 78,42  Bearing = 180 – 11,58 
= 168,42  = 168,42 
(3)

2.4 Marking criteria

 A = 50 mm
 B = 62 to 63 mm
  =110
Correct value of
 resultant force
250 mm Range: 88 to 90 mm
200 mm
110 (4)
[14]

QUESTION 3
Technical Sciences Examination FS/November 2023 MEMO
Grade 11

3.1 Vectors that are in the same plane.  (2)

3.2 F2 and F3 (2)

3.3 F2 and F3 or F1 and F3 or F1 and F2 (2)

3.4 40 N down (2)

3.5 POSITIVE MARKING FROM QUESTION 3.3

2 2 2 2 2
F R =F x + F y  ¿ ( 30 ) + ( 40 ) F R =50 N 
(3)

3.6 30 N,  left. 
The resultant along the y-axis is zero  forces are balanced. (3)
[14]

QUESTION 4

4.1 Normal (force)  (1)

4.2 OR/OF
FN F FN 
FV

fk FH
fk
T
T

w
w

Force ACCEPTED LABELS

F Fapplied
FN N/Fnormal/Normal force
fk f/Ffriction/Ff/Friction/Kinetic friction
w Fg/Fw/Weight/49 N/mg/Gravitational force
T Tension/ FT/ Force of string
FV Fy/Fvertical
FH Fx/Fhorizontal
(5)

4.3.1 N + Fy = mg 
27,87 + Fsin 25 = 5 x 9,8
, F = 50 N (4)

4.3.2 POSITIVE MARKING FROM QUESTION 4.3.1

Technical Sciences Examination FS/November 2023 MEMO
Grade 11

8 kg Block

T=f
= 41,22 N

5 Kg Block

Fx =T + f 
Fcos25 = T + f
50cos 25= 41,22 + f 
f = 4,10 N (5)
[15]

QUESTION 5

5.1.1 20 cm/ 0,2 m  (1)

5.1.2 Number of (complete) waves per second.  (2)

5.1.3 2 s  (1)

5.1.4 The lowermost point in a transverse wave.  (2)

5.1.5 OPTION 1 OPTION 2

v= ❑ 10= ❑ ¿ 20 m v=f 10=(0 , 5)¿ 20 m

T 2

(4)

5.2.1 Longitudinal (waves) 

Waves in which particles of the medium vibrate parallel to the direction of

propagation of the wave.  (3)

5.2.2 A – compression 
B – rarefaction  (2)

5.2.3 1,33 m  (2)

5.2.4 v = f 
= (1,33)(256) 
= 340,48 m·s-1  (3)

5.2.5 B and C  (1)

1 1
T= ¿ ¿ 0,004 s
f 256

Technical Sciences Examination FS/November 2023 MEMO
Grade 11

5.2.6

(3)
[24]

QUESTION 6

6.1.1 Echo is reflection of a sound wave. (2)

6.1.2 Longitudinal waves. (1)

6.2 The bouncing back of the of the waves from a surface.  (2)

6.3 Measure of how high or low a note is.  (2)

6.4.1 Diagram 3. It has lower amplitude.  (3)

6.4.2 Diagram 2. It has higher frequency.

(3)

6.5 Sound waves with frequencies greater than 20 000Hz.  (2)

6.6 Detect objects. 

To measure distances.
Determine the heartbeat of a foetus.
Measure speed of blood to detect narrowing of blood vessels
Determine the sex of the foetus.
Bone osmometry (bone fragility)
Treatment of soft tissue ailments (Any 2) (2)
[11]

QUESTION 7

7.1 Magnetic field is a region in space where another magnet or ferromagnetic

material will experience a force.  (2)

7.2
Marking criteria

 Shape
Correct direction from North to

South
 Lines not crossing

(3)

7.3.1 Attraction.  (1)

Technical Sciences Examination FS/November 2023 MEMO
Grade 11

7.3.2 North.
ACCEPT: N (1)

7.4 Aurora Borealis (Northern lights) 

OR Aurora Australis (Southern lights)
Magnetic storms (1)
[8]

QUESTION 8

8.1.1 The attraction or repulsion force between two point charges is directly
proportional to the product of the magnitude of the charges  and inversely
proportional to the square distances between the two charges.  (2)
−9
8.1.2 QS QT −4 9 7 , 2× 10 QT
F=k 2
5 , 18× 10 =9 ×10 2
r ( 0 , 03 )
−9
X =7 , 19× 10 C

(4)
8.1.3
Marking criteria
 Shape – curving at the + and
– ends.
 Field lines from positive to
negative
 Lines not crossing
(3)

8.2.1 Weight equals electrostatic force / Fg = FE  (1)

8.2.2 OPTION 1 OPTION 2

V 750 F VQ
E= ¿ 4
E= F E =F g EQ=mg =mg
−3 ¿ 3 ×10 d
d 25× 10 Q
750 ×Q −15
mg −15
4 , 8 ×10 ( 9 , 8 ) =4 , 8 ×1 0 ×9 , 8
¿ 3 ×1 04 = 25× 10
−3
Q Q
−18
−18 Q=1,568 × 10 C
Q=1,568 × 10 C

(5)
[16]
Technical Sciences Examination FS/November 2023 MEMO
Grade 11

QUESTION 9

9. 1 Potential difference across a cell  when the circuit is open.  (2)

9. 2 V = IR
6 = I(3) 
I = 2 A (3)

9.3 1 1 1
= +
R p R1 R2
1 1
¿ + R =4
12 3+3 p
RT =R p + R s8=4 + R
R=4 

(5)

9.4 OPTION 1 OPTION 2

Current across Current across 12 
parallel
V = IR
V = IR 12 = I(12) 
12 = I(4)  I=1A
I = 3 A Total current = 1 + 2
= 3 A (4)

9.5 POSITIVE MARKING FROM QUESTIONS 9.3 AND 9.4

OPTION 1 OPTION 2

Emf = VT  Emf = Vs + Vp

= ITRT = 3(4) + 12
= 3(8)  = 24 V
= 24 V (3)

9.6
V(V) 

I(A) (2)

9.7 Decrease
- Total resistance of the circuit increases. 
- As a result, the total current decreases 
According to Ohm’s law, V I  (4)
[23]
GRAND TOTAL: 150